Here's something I wrote in perl to encode mp3's ripped from a cd. It's not elegant, but it works.

---- Cut here----

#!/usr/bin/perl -w

# this is the SCSI device id $cd_device="1,3,0"; $encoder_options="-S -m s -q 0 --vbr-new -V 0 -b 192 -B 320 -f -k";

mkdir "riptemp"; chdir "riptemp";

system ("/usr/bin/cdda2wav -D $cd_device -B -L");

open (CDINDEX, "audio.cdindex") || die "Can't open file: audio.cdindex \n"; while (<CDINDEX>) { if (/Title>(.*)</) { $album=$1; } if (/Artist>(.*)</) { $artist=$1; } if (/Num="(\d+)">/) { $count=$1; } if (/Name>(.*)</) { $song[$count]=$1; }

} close CDINDEX;

@wavfiles=`ls *.wav`; chomp(@wavfiles);

@mp3files=@wavfiles;

for (0..$#mp3files) { $mp3files[$_]=~ s/wav/mp3/; }

for (0..$#wavfiles) { my $track; $track=$_ + 1; system(qq{/usr/local/bin/lame $encoder_options --tl "$album" --ta "$artist" --tt "$song[$track]" --tn $track $wavfiles[$_] $mp3files[$_]}); }

mkdir "../$artist"; mkdir "../$artist/$album";

for (0..$#mp3files) { my $track; $track=$_ +1; system(qq{ mv $mp3files[$_] "../$artist/$album/$artist - $album - $song[$track].mp3"}); }

system ("rm -f audio*"); chdir ".."; rmdir "riptemp";

---and here :-)-----

On Saturday 03 Jan 2004 3:58 pm, Syd Hancock wrote:

Hi all

I want to do something that I am sure is very simple but I am frustrated because I am not sure where to start.

Basically all I want to do is to feed all the files from a directory one by one into an application - i.e. using lame to encode wav files to mp3.

Can this be done from a bash script or should I use perl or ???

Any advice or info much appreciated.

Syd

You should be able to do this from bash but I have a feeling you can do it with lame itself. Have you man lame ?

Ian